\(\int \cos ^2(c+d x) (a+a \cos (c+d x))^{5/2} (A+C \cos ^2(c+d x)) \, dx\) [92]

Optimal result

Integrand size = 35, antiderivative size = 273 \[ \int \cos ^2(c+d x) (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\frac {2 a^3 (10439 A+8368 C) \sin (c+d x)}{6435 d \sqrt {a+a \cos (c+d x)}}+\frac {2 a^3 (2717 A+2224 C) \cos ^3(c+d x) \sin (c+d x)}{9009 d \sqrt {a+a \cos (c+d x)}}-\frac {4 a^2 (10439 A+8368 C) \sqrt {a+a \cos (c+d x)} \sin (c+d x)}{45045 d}+\frac {2 a^2 (143 A+136 C) \cos ^3(c+d x) \sqrt {a+a \cos (c+d x)} \sin (c+d x)}{1287 d}+\frac {2 a (10439 A+8368 C) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{15015 d}+\frac {10 a C \cos ^3(c+d x) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{143 d}+\frac {2 C \cos ^3(c+d x) (a+a \cos (c+d x))^{5/2} \sin (c+d x)}{13 d} \]

[Out]

2/15015*a*(10439*A+8368*C)*(a+a*cos(d*x+c))^(3/2)*sin(d*x+c)/d+10/143*a*C*cos(d*x+c)^3*(a+a*cos(d*x+c))^(3/2)*
sin(d*x+c)/d+2/13*C*cos(d*x+c)^3*(a+a*cos(d*x+c))^(5/2)*sin(d*x+c)/d+2/6435*a^3*(10439*A+8368*C)*sin(d*x+c)/d/
(a+a*cos(d*x+c))^(1/2)+2/9009*a^3*(2717*A+2224*C)*cos(d*x+c)^3*sin(d*x+c)/d/(a+a*cos(d*x+c))^(1/2)-4/45045*a^2
*(10439*A+8368*C)*sin(d*x+c)*(a+a*cos(d*x+c))^(1/2)/d+2/1287*a^2*(143*A+136*C)*cos(d*x+c)^3*sin(d*x+c)*(a+a*co
s(d*x+c))^(1/2)/d

Rubi [A] (verified)

Time = 1.02 (sec) , antiderivative size = 273, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.171, Rules used = {3125, 3055, 3060, 2838, 2830, 2725} \[ \int \cos ^2(c+d x) (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\frac {2 a^3 (2717 A+2224 C) \sin (c+d x) \cos ^3(c+d x)}{9009 d \sqrt {a \cos (c+d x)+a}}+\frac {2 a^3 (10439 A+8368 C) \sin (c+d x)}{6435 d \sqrt {a \cos (c+d x)+a}}+\frac {2 a^2 (143 A+136 C) \sin (c+d x) \cos ^3(c+d x) \sqrt {a \cos (c+d x)+a}}{1287 d}-\frac {4 a^2 (10439 A+8368 C) \sin (c+d x) \sqrt {a \cos (c+d x)+a}}{45045 d}+\frac {2 a (10439 A+8368 C) \sin (c+d x) (a \cos (c+d x)+a)^{3/2}}{15015 d}+\frac {10 a C \sin (c+d x) \cos ^3(c+d x) (a \cos (c+d x)+a)^{3/2}}{143 d}+\frac {2 C \sin (c+d x) \cos ^3(c+d x) (a \cos (c+d x)+a)^{5/2}}{13 d} \]

[In]

Int[Cos[c + d*x]^2*(a + a*Cos[c + d*x])^(5/2)*(A + C*Cos[c + d*x]^2),x]

[Out]

(2*a^3*(10439*A + 8368*C)*Sin[c + d*x])/(6435*d*Sqrt[a + a*Cos[c + d*x]]) + (2*a^3*(2717*A + 2224*C)*Cos[c + d
*x]^3*Sin[c + d*x])/(9009*d*Sqrt[a + a*Cos[c + d*x]]) - (4*a^2*(10439*A + 8368*C)*Sqrt[a + a*Cos[c + d*x]]*Sin
[c + d*x])/(45045*d) + (2*a^2*(143*A + 136*C)*Cos[c + d*x]^3*Sqrt[a + a*Cos[c + d*x]]*Sin[c + d*x])/(1287*d) +
(2*a*(10439*A + 8368*C)*(a + a*Cos[c + d*x])^(3/2)*Sin[c + d*x])/(15015*d) + (10*a*C*Cos[c + d*x]^3*(a + a*Co
s[c + d*x])^(3/2)*Sin[c + d*x])/(143*d) + (2*C*Cos[c + d*x]^3*(a + a*Cos[c + d*x])^(5/2)*Sin[c + d*x])/(13*d)

Rule 2725

Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[-2*b*(Cos[c + d*x]/(d*Sqrt[a + b*Sin[c + d*x
]])), x] /; FreeQ[{a, b, c, d}, x] && EqQ[a^2 - b^2, 0]

Rule 2830

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(-d
)*Cos[e + f*x]*((a + b*Sin[e + f*x])^m/(f*(m + 1))), x] + Dist[(a*d*m + b*c*(m + 1))/(b*(m + 1)), Int[(a + b*S
in[e + f*x])^m, x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] &&  !LtQ[m
, -2^(-1)]

Rule 2838

Int[sin[(e_.) + (f_.)*(x_)]^2*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Simp[(-Cos[e + f*x])*(
(a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 2))), x] + Dist[1/(b*(m + 2)), Int[(a + b*Sin[e + f*x])^m*(b*(m + 1) -
a*Sin[e + f*x]), x], x] /; FreeQ[{a, b, e, f, m}, x] && EqQ[a^2 - b^2, 0] &&  !LtQ[m, -2^(-1)]

Rule 3055

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_
.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(-b)*B*Cos[e + f*x]*(a + b*Sin[e + f*x])^(m - 1)*((c + d*Sin[e + f*x
])^(n + 1)/(d*f*(m + n + 1))), x] + Dist[1/(d*(m + n + 1)), Int[(a + b*Sin[e + f*x])^(m - 1)*(c + d*Sin[e + f*
x])^n*Simp[a*A*d*(m + n + 1) + B*(a*c*(m - 1) + b*d*(n + 1)) + (A*b*d*(m + n + 1) - B*(b*c*m - a*d*(2*m + n)))
*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, n}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] &
& NeQ[c^2 - d^2, 0] && GtQ[m, 1/2] &&  !LtQ[n, -1] && IntegerQ[2*m] && (IntegerQ[2*n] || EqQ[c, 0])

Rule 3060

Int[Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]]*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.
) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[-2*b*B*Cos[e + f*x]*((c + d*Sin[e + f*x])^(n + 1)/(d*f*(2*n + 3)*Sqrt
[a + b*Sin[e + f*x]])), x] + Dist[(A*b*d*(2*n + 3) - B*(b*c - 2*a*d*(n + 1)))/(b*d*(2*n + 3)), Int[Sqrt[a + b*
Sin[e + f*x]]*(c + d*Sin[e + f*x])^n, x], x] /; FreeQ[{a, b, c, d, e, f, A, B, n}, x] && NeQ[b*c - a*d, 0] &&
EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] &&  !LtQ[n, -1]

Rule 3125

Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.)*((A_.) + (C_.)*
sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Cos[e + f*x]*(a + b*Sin[e + f*x])^m*((c + d*Sin[e + f*x])^(
n + 1)/(d*f*(m + n + 2))), x] + Dist[1/(b*d*(m + n + 2)), Int[(a + b*Sin[e + f*x])^m*(c + d*Sin[e + f*x])^n*Si
mp[A*b*d*(m + n + 2) + C*(a*c*m + b*d*(n + 1)) + C*(a*d*m - b*c*(m + 1))*Sin[e + f*x], x], x], x] /; FreeQ[{a,
b, c, d, e, f, A, C, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] &&  !LtQ[m, -2^
(-1)] && NeQ[m + n + 2, 0]

Rubi steps \begin{align*} \text {integral}& = \frac {2 C \cos ^3(c+d x) (a+a \cos (c+d x))^{5/2} \sin (c+d x)}{13 d}+\frac {2 \int \cos ^2(c+d x) (a+a \cos (c+d x))^{5/2} \left (\frac {1}{2} a (13 A+6 C)+\frac {5}{2} a C \cos (c+d x)\right ) \, dx}{13 a} \\ & = \frac {10 a C \cos ^3(c+d x) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{143 d}+\frac {2 C \cos ^3(c+d x) (a+a \cos (c+d x))^{5/2} \sin (c+d x)}{13 d}+\frac {4 \int \cos ^2(c+d x) (a+a \cos (c+d x))^{3/2} \left (\frac {1}{4} a^2 (143 A+96 C)+\frac {1}{4} a^2 (143 A+136 C) \cos (c+d x)\right ) \, dx}{143 a} \\ & = \frac {2 a^2 (143 A+136 C) \cos ^3(c+d x) \sqrt {a+a \cos (c+d x)} \sin (c+d x)}{1287 d}+\frac {10 a C \cos ^3(c+d x) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{143 d}+\frac {2 C \cos ^3(c+d x) (a+a \cos (c+d x))^{5/2} \sin (c+d x)}{13 d}+\frac {8 \int \cos ^2(c+d x) \sqrt {a+a \cos (c+d x)} \left (\frac {15}{8} a^3 (143 A+112 C)+\frac {1}{8} a^3 (2717 A+2224 C) \cos (c+d x)\right ) \, dx}{1287 a} \\ & = \frac {2 a^3 (2717 A+2224 C) \cos ^3(c+d x) \sin (c+d x)}{9009 d \sqrt {a+a \cos (c+d x)}}+\frac {2 a^2 (143 A+136 C) \cos ^3(c+d x) \sqrt {a+a \cos (c+d x)} \sin (c+d x)}{1287 d}+\frac {10 a C \cos ^3(c+d x) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{143 d}+\frac {2 C \cos ^3(c+d x) (a+a \cos (c+d x))^{5/2} \sin (c+d x)}{13 d}+\frac {\left (a^2 (10439 A+8368 C)\right ) \int \cos ^2(c+d x) \sqrt {a+a \cos (c+d x)} \, dx}{3003} \\ & = \frac {2 a^3 (2717 A+2224 C) \cos ^3(c+d x) \sin (c+d x)}{9009 d \sqrt {a+a \cos (c+d x)}}+\frac {2 a^2 (143 A+136 C) \cos ^3(c+d x) \sqrt {a+a \cos (c+d x)} \sin (c+d x)}{1287 d}+\frac {2 a (10439 A+8368 C) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{15015 d}+\frac {10 a C \cos ^3(c+d x) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{143 d}+\frac {2 C \cos ^3(c+d x) (a+a \cos (c+d x))^{5/2} \sin (c+d x)}{13 d}+\frac {(2 a (10439 A+8368 C)) \int \left (\frac {3 a}{2}-a \cos (c+d x)\right ) \sqrt {a+a \cos (c+d x)} \, dx}{15015} \\ & = \frac {2 a^3 (2717 A+2224 C) \cos ^3(c+d x) \sin (c+d x)}{9009 d \sqrt {a+a \cos (c+d x)}}-\frac {4 a^2 (10439 A+8368 C) \sqrt {a+a \cos (c+d x)} \sin (c+d x)}{45045 d}+\frac {2 a^2 (143 A+136 C) \cos ^3(c+d x) \sqrt {a+a \cos (c+d x)} \sin (c+d x)}{1287 d}+\frac {2 a (10439 A+8368 C) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{15015 d}+\frac {10 a C \cos ^3(c+d x) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{143 d}+\frac {2 C \cos ^3(c+d x) (a+a \cos (c+d x))^{5/2} \sin (c+d x)}{13 d}+\frac {\left (a^2 (10439 A+8368 C)\right ) \int \sqrt {a+a \cos (c+d x)} \, dx}{6435} \\ & = \frac {2 a^3 (10439 A+8368 C) \sin (c+d x)}{6435 d \sqrt {a+a \cos (c+d x)}}+\frac {2 a^3 (2717 A+2224 C) \cos ^3(c+d x) \sin (c+d x)}{9009 d \sqrt {a+a \cos (c+d x)}}-\frac {4 a^2 (10439 A+8368 C) \sqrt {a+a \cos (c+d x)} \sin (c+d x)}{45045 d}+\frac {2 a^2 (143 A+136 C) \cos ^3(c+d x) \sqrt {a+a \cos (c+d x)} \sin (c+d x)}{1287 d}+\frac {2 a (10439 A+8368 C) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{15015 d}+\frac {10 a C \cos ^3(c+d x) (a+a \cos (c+d x))^{3/2} \sin (c+d x)}{143 d}+\frac {2 C \cos ^3(c+d x) (a+a \cos (c+d x))^{5/2} \sin (c+d x)}{13 d} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.78 (sec) , antiderivative size = 138, normalized size of antiderivative = 0.51 \[ \int \cos ^2(c+d x) (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\frac {a^2 \sqrt {a (1+\cos (c+d x))} (3233516 A+2798182 C+8 (222794 A+226573 C) \cos (c+d x)+(581152 A+746519 C) \cos (2 (c+d x))+148720 A \cos (3 (c+d x))+287060 C \cos (3 (c+d x))+20020 A \cos (4 (c+d x))+94010 C \cos (4 (c+d x))+23940 C \cos (5 (c+d x))+3465 C \cos (6 (c+d x))) \tan \left (\frac {1}{2} (c+d x)\right )}{720720 d} \]

[In]

Integrate[Cos[c + d*x]^2*(a + a*Cos[c + d*x])^(5/2)*(A + C*Cos[c + d*x]^2),x]

[Out]

(a^2*Sqrt[a*(1 + Cos[c + d*x])]*(3233516*A + 2798182*C + 8*(222794*A + 226573*C)*Cos[c + d*x] + (581152*A + 74
6519*C)*Cos[2*(c + d*x)] + 148720*A*Cos[3*(c + d*x)] + 287060*C*Cos[3*(c + d*x)] + 20020*A*Cos[4*(c + d*x)] +
94010*C*Cos[4*(c + d*x)] + 23940*C*Cos[5*(c + d*x)] + 3465*C*Cos[6*(c + d*x)])*Tan[(c + d*x)/2])/(720720*d)

Maple [A] (verified)

Time = 34.31 (sec) , antiderivative size = 156, normalized size of antiderivative = 0.57

method	result	size
default	\(\frac {8 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{3} \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (55440 C \left (\sin ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-262080 C \left (\sin ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (20020 A +520520 C \right ) \left (\sin ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-77220 A -566280 C \right ) \left (\sin ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (117117 A +369369 C \right ) \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-90090 A -150150 C \right ) \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+45045 A +45045 C \right ) \sqrt {2}}{45045 \sqrt {a \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}\, d}\)	\(156\)
parts	\(\frac {8 A \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{3} \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (140 \left (\cos ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-20 \left (\cos ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+39 \left (\cos ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+52 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+104\right ) \sqrt {2}}{315 \sqrt {a \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}\, d}+\frac {8 C \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{3} \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (55440 \left (\cos ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-70560 \left (\cos ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+41720 \left (\cos ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-3800 \left (\cos ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+4449 \left (\cos ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+5932 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+11864\right ) \sqrt {2}}{45045 \sqrt {a \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}\, d}\)	\(226\)

[In]

int(cos(d*x+c)^2*(a+cos(d*x+c)*a)^(5/2)*(A+C*cos(d*x+c)^2),x,method=_RETURNVERBOSE)

[Out]

8/45045*cos(1/2*d*x+1/2*c)*a^3*sin(1/2*d*x+1/2*c)*(55440*C*sin(1/2*d*x+1/2*c)^12-262080*C*sin(1/2*d*x+1/2*c)^1
0+(20020*A+520520*C)*sin(1/2*d*x+1/2*c)^8+(-77220*A-566280*C)*sin(1/2*d*x+1/2*c)^6+(117117*A+369369*C)*sin(1/2
*d*x+1/2*c)^4+(-90090*A-150150*C)*sin(1/2*d*x+1/2*c)^2+45045*A+45045*C)*2^(1/2)/(a*cos(1/2*d*x+1/2*c)^2)^(1/2)
/d

Fricas [A] (verification not implemented)

none

Time = 0.27 (sec) , antiderivative size = 151, normalized size of antiderivative = 0.55 \[ \int \cos ^2(c+d x) (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\frac {2 \, {\left (3465 \, C a^{2} \cos \left (d x + c\right )^{6} + 11970 \, C a^{2} \cos \left (d x + c\right )^{5} + 35 \, {\left (143 \, A + 523 \, C\right )} a^{2} \cos \left (d x + c\right )^{4} + 10 \, {\left (1859 \, A + 2092 \, C\right )} a^{2} \cos \left (d x + c\right )^{3} + 3 \, {\left (10439 \, A + 8368 \, C\right )} a^{2} \cos \left (d x + c\right )^{2} + 4 \, {\left (10439 \, A + 8368 \, C\right )} a^{2} \cos \left (d x + c\right ) + 8 \, {\left (10439 \, A + 8368 \, C\right )} a^{2}\right )} \sqrt {a \cos \left (d x + c\right ) + a} \sin \left (d x + c\right )}{45045 \, {\left (d \cos \left (d x + c\right ) + d\right )}} \]

[In]

integrate(cos(d*x+c)^2*(a+a*cos(d*x+c))^(5/2)*(A+C*cos(d*x+c)^2),x, algorithm="fricas")

[Out]

2/45045*(3465*C*a^2*cos(d*x + c)^6 + 11970*C*a^2*cos(d*x + c)^5 + 35*(143*A + 523*C)*a^2*cos(d*x + c)^4 + 10*(
1859*A + 2092*C)*a^2*cos(d*x + c)^3 + 3*(10439*A + 8368*C)*a^2*cos(d*x + c)^2 + 4*(10439*A + 8368*C)*a^2*cos(d
*x + c) + 8*(10439*A + 8368*C)*a^2)*sqrt(a*cos(d*x + c) + a)*sin(d*x + c)/(d*cos(d*x + c) + d)

Sympy [F(-1)]

Timed out. \[ \int \cos ^2(c+d x) (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\text {Timed out} \]

[In]

integrate(cos(d*x+c)**2*(a+a*cos(d*x+c))**(5/2)*(A+C*cos(d*x+c)**2),x)

[Out]

Timed out

Maxima [A] (verification not implemented)

none

Time = 0.49 (sec) , antiderivative size = 223, normalized size of antiderivative = 0.82 \[ \int \cos ^2(c+d x) (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\frac {572 \, {\left (35 \, \sqrt {2} a^{2} \sin \left (\frac {9}{2} \, d x + \frac {9}{2} \, c\right ) + 225 \, \sqrt {2} a^{2} \sin \left (\frac {7}{2} \, d x + \frac {7}{2} \, c\right ) + 756 \, \sqrt {2} a^{2} \sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ) + 2100 \, \sqrt {2} a^{2} \sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ) + 8190 \, \sqrt {2} a^{2} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} A \sqrt {a} + {\left (3465 \, \sqrt {2} a^{2} \sin \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right ) + 20475 \, \sqrt {2} a^{2} \sin \left (\frac {11}{2} \, d x + \frac {11}{2} \, c\right ) + 70070 \, \sqrt {2} a^{2} \sin \left (\frac {9}{2} \, d x + \frac {9}{2} \, c\right ) + 193050 \, \sqrt {2} a^{2} \sin \left (\frac {7}{2} \, d x + \frac {7}{2} \, c\right ) + 459459 \, \sqrt {2} a^{2} \sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ) + 1066065 \, \sqrt {2} a^{2} \sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ) + 3783780 \, \sqrt {2} a^{2} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} C \sqrt {a}}{1441440 \, d} \]

[In]

integrate(cos(d*x+c)^2*(a+a*cos(d*x+c))^(5/2)*(A+C*cos(d*x+c)^2),x, algorithm="maxima")

[Out]

1/1441440*(572*(35*sqrt(2)*a^2*sin(9/2*d*x + 9/2*c) + 225*sqrt(2)*a^2*sin(7/2*d*x + 7/2*c) + 756*sqrt(2)*a^2*s
in(5/2*d*x + 5/2*c) + 2100*sqrt(2)*a^2*sin(3/2*d*x + 3/2*c) + 8190*sqrt(2)*a^2*sin(1/2*d*x + 1/2*c))*A*sqrt(a)
+ (3465*sqrt(2)*a^2*sin(13/2*d*x + 13/2*c) + 20475*sqrt(2)*a^2*sin(11/2*d*x + 11/2*c) + 70070*sqrt(2)*a^2*sin
(9/2*d*x + 9/2*c) + 193050*sqrt(2)*a^2*sin(7/2*d*x + 7/2*c) + 459459*sqrt(2)*a^2*sin(5/2*d*x + 5/2*c) + 106606
5*sqrt(2)*a^2*sin(3/2*d*x + 3/2*c) + 3783780*sqrt(2)*a^2*sin(1/2*d*x + 1/2*c))*C*sqrt(a))/d

Giac [A] (verification not implemented)

none

Time = 6.91 (sec) , antiderivative size = 282, normalized size of antiderivative = 1.03 \[ \int \cos ^2(c+d x) (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\frac {\sqrt {2} {\left (3465 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) \sin \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right ) + 20475 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) \sin \left (\frac {11}{2} \, d x + \frac {11}{2} \, c\right ) + 10010 \, {\left (2 \, A a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 7 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )\right )} \sin \left (\frac {9}{2} \, d x + \frac {9}{2} \, c\right ) + 64350 \, {\left (2 \, A a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 3 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )\right )} \sin \left (\frac {7}{2} \, d x + \frac {7}{2} \, c\right ) + 27027 \, {\left (16 \, A a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 17 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )\right )} \sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ) + 15015 \, {\left (80 \, A a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 71 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )\right )} \sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ) + 180180 \, {\left (26 \, A a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right ) + 21 \, C a^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )\right )} \sin \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} \sqrt {a}}{1441440 \, d} \]

[In]

integrate(cos(d*x+c)^2*(a+a*cos(d*x+c))^(5/2)*(A+C*cos(d*x+c)^2),x, algorithm="giac")

[Out]

1/1441440*sqrt(2)*(3465*C*a^2*sgn(cos(1/2*d*x + 1/2*c))*sin(13/2*d*x + 13/2*c) + 20475*C*a^2*sgn(cos(1/2*d*x +
1/2*c))*sin(11/2*d*x + 11/2*c) + 10010*(2*A*a^2*sgn(cos(1/2*d*x + 1/2*c)) + 7*C*a^2*sgn(cos(1/2*d*x + 1/2*c))
)*sin(9/2*d*x + 9/2*c) + 64350*(2*A*a^2*sgn(cos(1/2*d*x + 1/2*c)) + 3*C*a^2*sgn(cos(1/2*d*x + 1/2*c)))*sin(7/2
*d*x + 7/2*c) + 27027*(16*A*a^2*sgn(cos(1/2*d*x + 1/2*c)) + 17*C*a^2*sgn(cos(1/2*d*x + 1/2*c)))*sin(5/2*d*x +
5/2*c) + 15015*(80*A*a^2*sgn(cos(1/2*d*x + 1/2*c)) + 71*C*a^2*sgn(cos(1/2*d*x + 1/2*c)))*sin(3/2*d*x + 3/2*c)
+ 180180*(26*A*a^2*sgn(cos(1/2*d*x + 1/2*c)) + 21*C*a^2*sgn(cos(1/2*d*x + 1/2*c)))*sin(1/2*d*x + 1/2*c))*sqrt(
a)/d

Mupad [F(-1)]

Timed out. \[ \int \cos ^2(c+d x) (a+a \cos (c+d x))^{5/2} \left (A+C \cos ^2(c+d x)\right ) \, dx=\int {\cos \left (c+d\,x\right )}^2\,\left (C\,{\cos \left (c+d\,x\right )}^2+A\right )\,{\left (a+a\,\cos \left (c+d\,x\right )\right )}^{5/2} \,d x \]

[In]

int(cos(c + d*x)^2*(A + C*cos(c + d*x)^2)*(a + a*cos(c + d*x))^(5/2),x)

[Out]

int(cos(c + d*x)^2*(A + C*cos(c + d*x)^2)*(a + a*cos(c + d*x))^(5/2), x)